Heat of Reaction.

>>> shake up of Reaction Aim: To determine the catch bam of reaction of NaOH with HCl Apparatus\Materials: Polythene Cup, Thermometer, Measuring Cylinder, NaOH, HCl. Procedure: (1) 25cm of HCl was situated in polythene cup, (2) HCl was left to stand for 5 transactions and then the temperature was taken (3) Steps 1-2 was repeat with NaOH instead of HCl, (4) NaOH was added to HCl in polythene cup and stirred for 5minutes and the highest temperature the liquid rose to was recorded. Results: initial temperature of NaOH - 32? Initial temperature of HCl - 31? Final temperature of mixture - 38? Temperature wage hike for NaOH = 6? Temperature rise for HCl = 7? playscript of mixture = 50cm Mass of dissolvent = 50g 1 cm of solution has a mass of 1g get of moles present in 25cm of NaOH = .0025moles Heat produced = 1365KJ Calculations: (1) Mass of 1cm of solution = 1g since the dumbness of the solution is 1g per cm, (2) Number of moles of NaOH = volume incmxconcentration in moles per dm 1000 cm = (25 x .1)/1000 = .0025moles (3) Heat produced = MC?? of NaOH+ MC?? of HCl = .

025kg X 4200 X (38?- 32?) NaOH = 630J (NaOH) = 025kg X 4200 X (38?- 31?) HCl = 735J (HCl) = 630J (NaOH) + 735J (HCl) = 1365J Conclusion: An heat-releasing reaction takes place when NaOH is miscellaneous with HCl. The amount of heat produced when .0025 moles of NaOH is mixed which .0025 Moles of HCl is equal to 1365J and the amount of heat that testament be produced when 1mole of NaOH reacts with 1mole of HCL will be equal to ((1 moles\ .1mole) X 1356j), 546KJ superb lab. Well organized. full(a ) conclusion. And excellent calculations!! ! Needs sources If you want to get a in force(p) essay, order it on our website: OrderEssay.net

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